What is the first derivative of 1+4x ?

The first derivative of 1+4x is 4

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derivative of 1+4x

\frac{d}{d x} (1 + 4 x)

4

Solution steps

\frac{d}{d x} (1 + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (4 x)

\frac{d}{d x} (1) = 0

\frac{d}{d x} (4 x) = 4

= 0 + 4

Simplify

= 4

f (x) = (\frac{x + 1}{x - 1})^{2}

y = x^{4} + 6 x^{2} - x

\int (4 x^{3} + x^{2} + 5) d x

\frac{\partial}{\partial y} (a x^{2} + b y^{2})

\int x (1 + x)^{\frac{2}{3}} d x