What is the solution for (dy)/(dx)=x^2e^{-4x}-4y ?

The solution for (dy)/(dx)=x^2e^{-4x}-4y is y=(x^3)/(3e^{4x)}+(c_{1})/(e^{4x)}

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(dy)/(dx)=x^2e^{-4x}-4y

\frac{d y}{d x} = x^{2} e^{- 4 x} - 4 y

y = \frac{x ^{3}}{3 e ^{4 x}} + \frac{c _{1}}{e ^{4 x}}

Solution steps

\frac{d y}{d x} = x^{2} e^{- 4 x} - 4 y

Solve linear ODE:

y = \frac{x ^{3}}{3 e ^{4 x}} + \frac{c _{1}}{e ^{4 x}}

y = \frac{x ^{3}}{3 e ^{4 x}} + \frac{c _{1}}{e ^{4 x}}

x \to - 1 lim (2 x^{3} - 5 x + 6 x - 1)

\int (sec^{2} (x) + 9) d x

\int e^{x + 7} d x

\frac{\partial}{\partial x} (ln (x^{4}))

\frac{15}{s ^{2} + 2 s + 5}

What is the solution for (dy)/(dx)=x^2e^{-4x}-4y ?
The solution for (dy)/(dx)=x^2e^{-4x}-4y is y=(x^3)/(3e^{4x)}+(c_{1})/(e^{4x)}