What is the solution for y^{''}-6y^'+9y=0,y(0)=-2,y^'(0)=1 ?

The solution for y^{''}-6y^'+9y=0,y(0)=-2,y^'(0)=1 is y=-2e^{3t}+7e^{3t}t

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y^{''}-6y^'+9y=0,y(0)=-2,y^'(0)=1

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = - 2, y^{^{'}} (0) = 1

y = - 2 e^{3 t} + 7 e^{3 t} t

Solution steps

y^{''} (t) - 6 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = - 2 e^{3 t} + 7 e^{3 t} t

y = - 2 e^{3 t} + 7 e^{3 t} t

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\frac{d y}{d x} + 2 y = 9 e^{x}

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What is the solution for y^{''}-6y^'+9y=0,y(0)=-2,y^'(0)=1 ?
The solution for y^{''}-6y^'+9y=0,y(0)=-2,y^'(0)=1 is y=-2e^{3t}+7e^{3t}t