What is the derivative of (x^4/(16)) ?

The derivative of (x^4/(16)) is (x^3)/4

What is the first derivative of (x^4/(16)) ?

The first derivative of (x^4/(16)) is (x^3)/4

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\frac{d}{d x} (\frac{x ^{4}}{16})

\frac{x ^{3}}{4}

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{16})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{16} \frac{d}{d x} (x^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{16} \cdot 4 x^{4 - 1}

Simplify

\frac{1}{16} \cdot 4 x^{4 - 1} : \frac{x ^{3}}{4}

= \frac{x ^{3}}{4}

\frac{d ^{2}}{d x ^{2}} (3 x^{2})

x \to 0 lim (\frac{2}{3} x^{- \frac{1}{3}})

\int e^{t} - 1 d t

\int_{- 6}^{6} (e^{x} - e^{- x})^{2} d x

\frac{cos ( t )}{t ^{7}}

What is the derivative of (x^4/(16)) ?
The derivative of (x^4/(16)) is (x^3)/4
What is the first derivative of (x^4/(16)) ?
The first derivative of (x^4/(16)) is (x^3)/4