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Popular >

area y=3(x^3-x),y=0

Solution

area

y = 3 (x^{3} - x), y = 0

Solution

\frac{3}{2}

+1

Decimal Notation

1.5

Solution steps

Apply the area formula:

\int_{- 1}^{1} 3 x^{3} - x d x

Solve

\int_{- 1}^{1} 3 x^{3} - x d x : \frac{3}{2}

The area is:

= \frac{3}{2}

Popular Examples

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y^{^{'}} = - \frac{x}{y} + \frac{( x ^{2} + y ^{2} )}{y}

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\int_{c}^{d} \int_{a}^{b} 1 + x + y d x d y

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\int \frac{1}{2 x ^{2} + 4} d x

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\int \frac{1}{a ^{2} sin ^{2} ( x ) + b ^{2} cos ^{2} ( x )} d x

Frequently Asked Questions (FAQ)

What is area y=3(x^3-x),y=0 ?
The answer to area y=3(x^3-x),y=0 is 3/2