What is the derivative of (4x-3)^4 ?

The derivative of (4x-3)^4 is 16(4x-3)^3

What is the first derivative of (4x-3)^4 ?

The first derivative of (4x-3)^4 is 16(4x-3)^3

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derivative of

(4 x - 3)^{4}

16 (4 x - 3)^{3}

Solution steps

\frac{d}{d x} ((4 x - 3)^{4})

Apply the chain rule:

4 (4 x - 3)^{3} \frac{d}{d x} (4 x - 3)

= 4 (4 x - 3)^{3} \frac{d}{d x} (4 x - 3)

\frac{d}{d x} (4 x - 3) = 4

= 4 (4 x - 3)^{3} \cdot 4

Simplify

= 16 (4 x - 3)^{3}

f (x) = (- 9 x^{2} + 4)^{2}

\int x arctan (7 x) d x

\frac{d y}{d t} = 5 - 2 y

\int sin (w x) d x

f (x) = 9 x^{3}

What is the derivative of (4x-3)^4 ?
The derivative of (4x-3)^4 is 16(4x-3)^3
What is the first derivative of (4x-3)^4 ?
The first derivative of (4x-3)^4 is 16(4x-3)^3