What is the limit as z approaches 0 of (sin(z))/z ?

The limit as z approaches 0 of (sin(z))/z is 1

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limit as z approaches 0 of (sin(z))/z

z \to 0 lim (\frac{sin ( z )}{z})

1

Solution steps

z \to 0 lim (\frac{sin ( z )}{z})

Apply L'Hopital's Rule

: z \to 0 lim (\frac{cos ( z )}{1})

= z \to 0 lim (\frac{cos ( z )}{1})

Plug in the value

z = 0

= \frac{cos ( 0 )}{1}

Simplify

\frac{cos ( 0 )}{1} : 1

= 1

\int 2 + x d x

x \to 1 lim (a x^{2} + b x + c)

x \to + 0 + lim (\frac{1}{x ^{\frac{2}{3}}})

x^{2} + 3

\int_{0}^{6} 2 π (6 - x) (6 x - x^{2}) d x

What is the limit as z approaches 0 of (sin(z))/z ?
The limit as z approaches 0 of (sin(z))/z is 1