What is the tangent of y=x^4+3e^x,(0,3) ?

The tangent of y=x^4+3e^x,(0,3) is y=3x+3

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tangent of y=x^4+3e^x,(0,3)

tangent of

y = x^{4} + 3 e^{x}, (0, 3)

y = 3 x + 3

Solution steps

Find the slope of

y = x^{4} + 3 e^{x} : \frac{d y}{d x} = 4 x^{3} + 3 e^{x}

Compute the slope of

y = x^{4} + 3 e^{x}

(0, 3) : m = 3

Find the line with slope m=

3

and passing through

(0, 3) : y = 3 x + 3

y = 3 x + 3

\int x (sin (x) - 2) d x

\frac{\partial}{\partial x} (4^{(x^{9})})

\frac{d ^{2}}{d x ^{2}} (4 cos (x))

f (x) = \frac{4}{x ^{5}}

x \to - 2 lim (x^{2} + 5 x)

What is the tangent of y=x^4+3e^x,(0,3) ?
The tangent of y=x^4+3e^x,(0,3) is y=3x+3