What is the derivative of x+sin(2x) ?

The derivative of x+sin(2x) is 1+cos(2x)*2

What is the first derivative of x+sin(2x) ?

The first derivative of x+sin(2x) is 1+cos(2x)*2

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\frac{d}{d x} (x + sin (2 x))

1 + cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (x + sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (sin (2 x))

\frac{d x}{d x} = 1

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 1 + cos (2 x) \cdot 2

\frac{d}{d x} \frac{( x ^{2} + 2 ) ^{\frac{3}{2}}}{3}

\int_{0}^{27} \frac{3}{x ^{\frac{2}{3}}} d x

11 e^{x^{2}}

\int - 1 (x - 4) d x

t \to π lim (\frac{t}{π})

What is the derivative of x+sin(2x) ?
The derivative of x+sin(2x) is 1+cos(2x)*2
What is the first derivative of x+sin(2x) ?
The first derivative of x+sin(2x) is 1+cos(2x)*2