What is maclaurin x-sin(x) ?

The answer to maclaurin x-sin(x) is 1/6 x^3-1/120 x^5+1/5040 x^7-1/362880 x^9+\ldots

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maclaurin x-sin(x)

maclaurin

x - sin (x)

\frac{1}{6} x^{3} - \frac{1}{120} x^{5} + \frac{1}{5040} x^{7} - \frac{1}{362880} x^{9} + \dots

Solution steps

Apply the Maclaurin Formula

= 0 + \frac{\frac{d}{d x} ( x - sin ( x ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x - sin ( x ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x - sin ( x ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{0}{1 !} x + \frac{0}{2 !} x^{2} + \frac{1}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{- 1}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{1}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{- 1}{9 !} x^{9} + \frac{0}{10 !} x^{10} + \dots

Refine

= \frac{1}{6} x^{3} - \frac{1}{120} x^{5} + \frac{1}{5040} x^{7} - \frac{1}{362880} x^{9} + \dots

\frac{d}{d x} (ln (sin (10 x)))

y^{^{''}} + 6 y^{^{'}} - 16 y = - 272 sin (8 x)

\frac{d}{d x} (\frac{ln ( cos ( 2 x ) )}{x})

\frac{d}{d x} (2 x e^{- 4 x})

y = sin (3 x) + cos (8 x)

What is maclaurin x-sin(x) ?
The answer to maclaurin x-sin(x) is 1/6 x^3-1/120 x^5+1/5040 x^7-1/362880 x^9+\ldots