What is the derivative of 3x^2+4x-4 ?

The derivative of 3x^2+4x-4 is 6x+4

What is the first derivative of 3x^2+4x-4 ?

The first derivative of 3x^2+4x-4 is 6x+4

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\frac{d}{d x} (3 x^{2} + 4 x - 4)

6 x + 4

Solution steps

\frac{d}{d x} (3 x^{2} + 4 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (4)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (4) = 0

= 6 x + 4 - 0

Simplify

= 6 x + 4

n = 2 \sum \infty \frac{1}{2 ^{n} - 1}

\int (e^{t} + 1)^{2} d t

x \to 2 lim (\frac{1}{x + 1})

\int \frac{sec ^{2} ( 6 x )}{tan ( 6 x ) + 2} d x

\frac{3 s}{s ^{2} + 3 s + 16}

What is the derivative of 3x^2+4x-4 ?
The derivative of 3x^2+4x-4 is 6x+4
What is the first derivative of 3x^2+4x-4 ?
The first derivative of 3x^2+4x-4 is 6x+4