What is the integral of 2/u ?

The integral of 2/u is 2ln|u|+C

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integral of 2/u

\int \frac{2}{u} d u

2 ln ∣ u ∣ + C

Solution steps

\int \frac{2}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 2 ln ∣ u ∣

Add a constant to the solution

= 2 ln ∣ u ∣ + C

y^{^{''}} - 12 y^{^{'}} + 52 y = 0

\int_{0}^{1} (1 - x)^{9} d x

f (x) = 7 x + 9

f (x) = 18 x^{2} - 27 x

\frac{\partial}{\partial x} ((x^{3} - y^{2})^{2})