What is the derivative of 18x+ln(18x) ?

The derivative of 18x+ln(18x) is 18+1/x

What is the first derivative of 18x+ln(18x) ?

The first derivative of 18x+ln(18x) is 18+1/x

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\frac{d}{d x} (18 x + ln (18 x))

18 + \frac{1}{x}

Solution steps

\frac{d}{d x} (18 x + ln (18 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (18 x) + \frac{d}{d x} (ln (18 x))

\frac{d}{d x} (18 x) = 18

\frac{d}{d x} (ln (18 x)) = \frac{1}{x}

= 18 + \frac{1}{x}

n = 0 \sum \infty \frac{n}{4 ^{n}}

\int sin (6 x) cos (4 x) d x

\int x^{3} d x

\frac{d}{d x} (- 4 x^{2} + 2 x - 3)

- 2 x^{4} (4 x^{2} + 1)^{3}

What is the derivative of 18x+ln(18x) ?
The derivative of 18x+ln(18x) is 18+1/x
What is the first derivative of 18x+ln(18x) ?
The first derivative of 18x+ln(18x) is 18+1/x