What is laplacetransform cos(4x) ?

The answer to laplacetransform cos(4x) is s/(s^2+16)

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laplacetransform cos(4x)

laplace transform

cos (4 x)

\frac{s}{s ^{2} + 16}

Solution steps

L {cos (4 x)}

Use Laplace Transform table:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (4 x)} = \frac{s}{s ^{2} + 4 ^{2}}

= \frac{s}{s ^{2} + 4 ^{2}}

= \frac{s}{s ^{2} + 16}

- \frac{6}{( 3 x + 5 ) ^{2}}

\int_{3}^{\infty} e^{7 x} d x

\frac{\partial}{\partial x} (3 x (5 + y)^{- 1})

\frac{d y}{d x} + y = 1, y (0) = 1

\frac{\partial}{\partial y} ((y - x^{2})^{2} + x^{5})

What is laplacetransform cos(4x) ?
The answer to laplacetransform cos(4x) is s/(s^2+16)