What is the integral from 0 to 1 of (sqrt(x)) ?

The integral from 0 to 1 of (sqrt(x)) is 2/3

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integral from 0 to 1 of (sqrt(x))

\int_{0}^{1} (x) d x

\frac{2}{3}

Decimal

0.66666 \dots

Solution steps

\int_{0}^{1} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

= [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

Compute the boundaries:

\frac{2}{3}

= \frac{2}{3}

\int \frac{3 ( 1 - tan ^{2} ( x ) )}{sec ^{2} ( x )} d x

2 x sin (x^{2})

\frac{d}{d x} (\frac{b a ^{2} - x ^{2}}{a})

x \to 3 lim (2 x + 5)

\frac{d}{d x} (\frac{4}{x ^{11}})

What is the integral from 0 to 1 of (sqrt(x)) ?
The integral from 0 to 1 of (sqrt(x)) is 2/3