What is the integral from 0 to 3 of 3x ?

The integral from 0 to 3 of 3x is 27/2

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integral from 0 to 3 of 3x

\int_{0}^{3} 3 x d x

\frac{27}{2}

Decimal

13.5

Solution steps

\int_{0}^{3} 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{3} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{3}

= 3 [\frac{x ^{2}}{2}]_{0}^{3}

Compute the boundaries:

\frac{9}{2}

= 3 \cdot \frac{9}{2}

Simplify

= \frac{27}{2}

\frac{d}{d x} (tan (\frac{1 - e ^{x}}{1 + e ^{x}}))

x \to 0 lim (\frac{1}{cos ( 5 x )})

f (x) = e^{x + 1}

x \to 6 lim (\frac{( \frac{1}{x} - \frac{1}{6} )}{x - 6})

\frac{d}{d x} (arccos (3 x) - 2 sinh (\frac{x}{5}))