What is the solution for (dy)/(dx)=-(1+y)^4 ?

The solution for (dy)/(dx)=-(1+y)^4 is y=\sqrt[3]{1/(3(x+c_{1))}}-1

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(dy)/(dx)=-(1+y)^4

\frac{d y}{d x} = - (1 + y)^{4}

y = 3 \frac{1}{3 ( x + c _{1} )} - 1

Solution steps

\frac{d y}{d x} = - (1 + y)^{4}

Solve separable ODE:

y = 3 \frac{1}{3 ( x + c _{1} )} - 1

y = 3 \frac{1}{3 ( x + c _{1} )} - 1

y^{^{''}} = sin (3 x - \frac{π}{3})

f (x) = 7 e^{- 4 x}

\int \frac{( e ^{x} + 9 )}{e ^{2 x} - 6 e ^{x} + 9} d x

f (x) = x^{2} + 3, (- 3, 12)

\frac{\partial}{\partial x} (f (x, y) (x + y))

What is the solution for (dy)/(dx)=-(1+y)^4 ?
The solution for (dy)/(dx)=-(1+y)^4 is y=\sqrt[3]{1/(3(x+c_{1))}}-1