What is the solution for y^{''}+y=0,y(0)=0,y^'(0)=1 ?

The solution for y^{''}+y=0,y(0)=0,y^'(0)=1 is y=sin(t)

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y^{''}+y=0,y(0)=0,y^'(0)=1

y^{^{''}} + y = 0, y (0) = 0, y^{^{'}} (0) = 1

y = sin (t)

Solution steps

y^{''} (t) + y = 0

Solve linear ODE:

y = sin (t)

y = sin (t)

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\frac{\partial}{\partial x} (\frac{x}{x ^{5} - y ^{7}})

e^{- 2 a x}

\frac{d}{d x} (e^{- 13 x})

\int \frac{cos ( ln ( x ) )}{x} d x

What is the solution for y^{''}+y=0,y(0)=0,y^'(0)=1 ?
The solution for y^{''}+y=0,y(0)=0,y^'(0)=1 is y=sin(t)