What is (\partial)/(\partial x)(zsin^2(x)) ?

The answer to (\partial)/(\partial x)(zsin^2(x)) is z*2sin(x)cos(x)

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(\partial)/(\partial x)(zsin^2(x))

\frac{\partial}{\partial x} (z sin^{2} (x))

z \cdot 2 sin (x) cos (x)

Solution steps

\frac{\partial}{\partial x} (z sin^{2} (x))

Treat

z

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial x} (sin^{2} (x))

Apply the chain rule:

2 sin (x) \frac{\partial}{\partial x} (sin (x))

= 2 sin (x) \frac{\partial}{\partial x} (sin (x))

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= z \cdot 2 sin (x) cos (x)

f (x) = cos (6 x) \cdot 6

\frac{d}{d x} (2 x^{3} + \frac{1}{24 x})

x \to 2 lim (\frac{1 - x}{x - 2})

\frac{- 2 ( x - 9 )}{x ^{4}}

\int \frac{3 x + 12}{x ^{3} + 4 x ^{2} + 4 x} d x

What is (\partial)/(\partial x)(zsin^2(x)) ?
The answer to (\partial)/(\partial x)(zsin^2(x)) is z*2sin(x)cos(x)