What is the derivative of f(x)=1-x^2 ?

The derivative of f(x)=1-x^2 is -2x

What is the first derivative of f(x)=1-x^2 ?

The first derivative of f(x)=1-x^2 is -2x

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derivative of

f (x) = 1 - x^{2}

- 2 x

Solution steps

\frac{d}{d x} (1 - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 0 - 2 x

Simplify

= - 2 x

\int \frac{1}{( 5 - x ^{2} ) ^{\frac{3}{2}}} d x

\frac{1}{( s + 1 )}

\frac{t - 1}{t ^{2} + 2 t + 1}

\int x sin (x + y) d x

(1 + x^{3})^{2020}

What is the derivative of f(x)=1-x^2 ?
The derivative of f(x)=1-x^2 is -2x
What is the first derivative of f(x)=1-x^2 ?
The first derivative of f(x)=1-x^2 is -2x