What is the solution for (dy)/(dt)=-y^2,y(0)= 1/2 ?

The solution for (dy)/(dt)=-y^2,y(0)= 1/2 is y= 1/(t+2)

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(dy)/(dt)=-y^2,y(0)= 1/2

\frac{d y}{d t} = - y^{2}, y (0) = \frac{1}{2}

y = \frac{1}{t + 2}

Solution steps

\frac{d y}{d t} = - y^{2}

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y = \frac{1}{t + 2}

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What is the solution for (dy)/(dt)=-y^2,y(0)= 1/2 ?
The solution for (dy)/(dt)=-y^2,y(0)= 1/2 is y= 1/(t+2)