What is the tangent of f(x)=x^2,(5/3 , 25/9) ?

The tangent of f(x)=x^2,(5/3 , 25/9) is y= 10/3 x-25/9

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tangent of f(x)=x^2,(5/3 , 25/9)

tangent of

f (x) = x^{2}, (\frac{5}{3}, \frac{25}{9})

y = \frac{10}{3} x - \frac{25}{9}

Solution steps

Find the slope of

f (x) = x^{2} : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{10}{3}

Find the line with slope m=

\frac{10}{3}

and passing through

(\frac{5}{3}, \frac{25}{9}) : y = \frac{10}{3} x - \frac{25}{9}

y = \frac{10}{3} x - \frac{25}{9}

\int t e^{(4 - s) t} d t

\int 4^{2 x} d x

\frac{2}{s ^{3} + 3 s ^{2} - 4}

\int_{0}^{2} 36 x + 73 d x

\frac{\partial}{\partial x} (I n (3 x^{2} y))

What is the tangent of f(x)=x^2,(5/3 , 25/9) ?
The tangent of f(x)=x^2,(5/3 , 25/9) is y= 10/3 x-25/9