What is (\partial)/(\partial y)((x-y)^2) ?

The answer to (\partial)/(\partial y)((x-y)^2) is -2(x-y)

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(\partial)/(\partial y)((x-y)^2)

\frac{\partial}{\partial y} ((x - y)^{2})

- 2 (x - y)

Solution steps

\frac{\partial}{\partial y} ((x - y)^{2})

Treat

x

as a constant

Apply the chain rule:

2 (x - y) \frac{\partial}{\partial y} (x - y)

= 2 (x - y) \frac{\partial}{\partial y} (x - y)

\frac{\partial}{\partial y} (x - y) = - 1

= 2 (x - y) (- 1)

Simplify

= - 2 (x - y)

a

y^{^{''}} - 8 y^{^{'}} + 14 y = 0, y (0) = 0, y^{^{'}} (0) = 1

\frac{\partial ^{2}}{\partial x ^{2}} (\frac{x y}{x - y})

y^{^{''}} - 16 y^{^{'}} + 64 y = 5 t^{- 1} e^{8 t}

\int cos (2 t) + sin (2 t) d t

What is (\partial)/(\partial y)((x-y)^2) ?
The answer to (\partial)/(\partial y)((x-y)^2) is -2(x-y)