What is the derivative of 2x^2+3/x ?

The derivative of 2x^2+3/x is 4x-3/(x^2)

What is the first derivative of 2x^2+3/x ?

The first derivative of 2x^2+3/x is 4x-3/(x^2)

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\frac{d}{d x} (2 x^{2} + \frac{3}{x})

4 x - \frac{3}{x ^{2}}

Solution steps

\frac{d}{d x} (2 x^{2} + \frac{3}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (\frac{3}{x})

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (\frac{3}{x}) = - \frac{3}{x ^{2}}

= 4 x - \frac{3}{x ^{2}}

\int \frac{2 x + 4}{4 - 4 x ^{2}} d x

\int 4 y^{2} d y

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 36})

\int \frac{1}{x ^{2} - 5} d x

n = 1 \sum \infty 5

What is the derivative of 2x^2+3/x ?
The derivative of 2x^2+3/x is 4x-3/(x^2)
What is the first derivative of 2x^2+3/x ?
The first derivative of 2x^2+3/x is 4x-3/(x^2)