What is the tangent of y=sqrt(3)x+2cos(x) ?

The tangent of y=sqrt(3)x+2cos(x) is y=(sqrt(3)-2sin(a_{0}))x+2a_{0}sin(a_{0})+2cos(a_{0})

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tangent of y=sqrt(3)x+2cos(x)

tangent of

y = 3 x + 2 cos (x)

y = (3 - 2 sin (a_{0})) x + 2 a_{0} sin (a_{0}) + 2 cos (a_{0})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0} + 2 cos (a_{0}))

Find the slope of

y = 3 x + 2 cos (x) : \frac{d y}{d x} = 3 - 2 sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3 - 2 sin (a_{0})

Find the line with slope m=

3 - 2 sin (a_{0})

and passing through

(a_{0}, 3 a_{0} + 2 cos (a_{0})) : y = (3 - 2 sin (a_{0})) x + 2 a_{0} sin (a_{0}) + 2 cos (a_{0})

y = (3 - 2 sin (a_{0})) x + 2 a_{0} sin (a_{0}) + 2 cos (a_{0})

y = x^{4} - 3 x^{2} + 8, at x = 1

\int (\frac{1}{x ^{5}} - x^{5} - \frac{1}{9}) d x

x \to - 2 - lim (- 4 x - 8 + 3)

\frac{d}{d x} (tanh (1 + e^{4 x}))

x \to - \infty lim (3 x^{2} + 1)

What is the tangent of y=sqrt(3)x+2cos(x) ?
The tangent of y=sqrt(3)x+2cos(x) is y=(sqrt(3)-2sin(a_{0}))x+2a_{0}sin(a_{0})+2cos(a_{0})