What is area x^2-2x+2, 1/2 (x-4)^2,x=0 ?

The answer to area x^2-2x+2, 1/2 (x-4)^2,x=0 is 128/3

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area x^2-2x+2, 1/2 (x-4)^2,x=0

area

x^{2} - 2 x + 2, \frac{1}{2} (x - 4)^{2}, x = 0

\frac{128}{3}

Decimal

42.66666 \dots

Solution steps

Apply the area formula:

\int_{- 6}^{2} x^{2} - 2 x + 2 - \frac{1}{2} (x - 4)^{2} d x

Solve

\int_{- 6}^{2} x^{2} - 2 x + 2 - \frac{1}{2} (x - 4)^{2} d x : \frac{128}{3}

The area is:

= \frac{128}{3}

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What is area x^2-2x+2, 1/2 (x-4)^2,x=0 ?
The answer to area x^2-2x+2, 1/2 (x-4)^2,x=0 is 128/3