What is the tangent of f(x)=4x^3-24x^2,\at x=-3 ?

The tangent of f(x)=4x^3-24x^2,\at x=-3 is y=252x+432

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=4x^3-24x^2,\at x=-3

tangent of

f (x) = 4 x^{3} - 24 x^{2}, at x = - 3

y = 252 x + 432

Solution steps

Find the tangent point:

(- 3, - 324)

Find the slope of

f (x) = 4 x^{3} - 24 x^{2} : \frac{df ( x )}{d x} = 12 x^{2} - 48 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 252

Find the line with slope m=

252

and passing through

(- 3, - 324) : y = 252 x + 432

y = 252 x + 432

\frac{\partial}{\partial x} (4 x - y^{2} + 2 z^{2})

y = 2 e^{x^{2} + 5 x + 9}

\int 8 sin (x) d x

\frac{\partial}{\partial x} (100 \cdot (y - x^{2})^{2})

3 + 7 t + t^{2} + δ (t)

What is the tangent of f(x)=4x^3-24x^2,\at x=-3 ?
The tangent of f(x)=4x^3-24x^2,\at x=-3 is y=252x+432