What is the derivative of arcsin(8x)+arccos(8x) ?

The derivative of arcsin(8x)+arccos(8x) is 0

What is the first derivative of arcsin(8x)+arccos(8x) ?

The first derivative of arcsin(8x)+arccos(8x) is 0

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derivative of

arcsin (8 x) + arccos (8 x)

0

Solution steps

\frac{d}{d x} (arcsin (8 x) + arccos (8 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (arcsin (8 x)) + \frac{d}{d x} (arccos (8 x))

\frac{d}{d x} (arcsin (8 x)) = \frac{8}{1 - 64 x ^{2}}

\frac{d}{d x} (arccos (8 x)) = - \frac{8}{1 - 64 x ^{2}}

= \frac{8}{1 - 64 x ^{2}} - \frac{8}{1 - 64 x ^{2}}

Simplify

= 0

x \to + 0 lim (\frac{sin ( 5 x )}{5})

n = 1 \sum \infty \frac{x ^{n}}{n 5 ^{n}}

\int 27 tan^{3} (x) sec (x) d x

- \frac{5}{x ^{2} + 3}

\int \frac{x ^{4}}{( 1 - x ) ^{3}} d x

What is the derivative of arcsin(8x)+arccos(8x) ?
The derivative of arcsin(8x)+arccos(8x) is 0
What is the first derivative of arcsin(8x)+arccos(8x) ?
The first derivative of arcsin(8x)+arccos(8x) is 0