What is the integral of 1/(x(\sqrt[3]{x))} ?

The integral of 1/(x(\sqrt[3]{x))} is -3/(\sqrt[3]{x)}+C

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integral of 1/(x(\sqrt[3]{x))}

\int \frac{1}{x ( 3 x )} d x

- \frac{3}{3 x} + C

Solution steps

\int \frac{1}{x 3 x} d x

Simplify

x 3 x : x^{\frac{4}{3}}

= \int \frac{1}{x ^{\frac{4}{3}}} d x

Apply the Power Rule

: - \frac{3}{3 x}

= - \frac{3}{3 x}

Add a constant to the solution

= - \frac{3}{3 x} + C

\int \frac{4 x}{x ^{2} - 9} d x

n = 1 \sum \infty 3 x^{n}

\frac{4 x ^{2} - 7 x + 5}{2 x + 1}

\int x^{2} - 5 x + 4 d x

n = 0 \sum \infty \frac{1}{10 0 ^{n}}

What is the integral of 1/(x(\sqrt[3]{x))} ?
The integral of 1/(x(\sqrt[3]{x))} is -3/(\sqrt[3]{x)}+C