What is the derivative of arcsec(2x) ?

The derivative of arcsec(2x) is 1/(sqrt(x^2)\sqrt{4x^2-1)}

What is the first derivative of arcsec(2x) ?

The first derivative of arcsec(2x) is 1/(sqrt(x^2)\sqrt{4x^2-1)}

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derivative of

arcsec (2 x)

\frac{1}{x ^{2} 4 x ^{2} - 1}

Solution steps

\frac{d}{d x} (arcsec (2 x))

Apply the chain rule:

\frac{1}{( 2 x ) ^{2} ( 2 x ) ^{2} - 1} \frac{d}{d x} (2 x)

= \frac{1}{( 2 x ) ^{2} ( 2 x ) ^{2} - 1} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= \frac{1}{( 2 x ) ^{2} ( 2 x ) ^{2} - 1} \cdot 2

Simplify

\frac{1}{( 2 x ) ^{2} ( 2 x ) ^{2} - 1} \cdot 2 : \frac{1}{x ^{2} 4 x ^{2} - 1}

= \frac{1}{x ^{2} 4 x ^{2} - 1}

\int \frac{x + 2}{x ^{2} - 2 x - 15} d x

x \to 1 lim (3 (x - 1)^{2})

tan (\frac{x}{y}) = x + y

f (x) = arctan (\frac{x}{2}), at x = 2

2 x + 6, - 2, 2

What is the derivative of arcsec(2x) ?
The derivative of arcsec(2x) is 1/(sqrt(x^2)\sqrt{4x^2-1)}
What is the first derivative of arcsec(2x) ?
The first derivative of arcsec(2x) is 1/(sqrt(x^2)\sqrt{4x^2-1)}