What is the integral of 7v(v^2+2)^2 ?

The integral of 7v(v^2+2)^2 is 7((v^6)/6+v^4+2v^2)+C

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integral of 7v(v^2+2)^2

\int 7 v (v^{2} + 2)^{2} d v

7 (\frac{v ^{6}}{6} + v^{4} + 2 v^{2}) + C

Solution steps

\int 7 v (v^{2} + 2)^{2} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int v (v^{2} + 2)^{2} d v

Expand

v (v^{2} + 2)^{2} : v^{5} + 4 v^{3} + 4 v

= 7 \cdot \int v^{5} + 4 v^{3} + 4 v d v

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 7 (\int v^{5} d v + \int 4 v^{3} d v + \int 4 v d v)

\int v^{5} d v = \frac{v ^{6}}{6}

\int 4 v^{3} d v = v^{4}

\int 4 v d v = 2 v^{2}

= 7 (\frac{v ^{6}}{6} + v^{4} + 2 v^{2})

Add a constant to the solution

= 7 (\frac{v ^{6}}{6} + v^{4} + 2 v^{2}) + C

\frac{d}{d θ} (3 + 2 sin (θ))

f (x) = \frac{x + x}{x ^{2}}

- \frac{14}{s ^{5}}

f (x) = 3 4 - 9 x

\frac{\partial}{\partial t} (e^{- 6 t} cos (π x))

What is the integral of 7v(v^2+2)^2 ?
The integral of 7v(v^2+2)^2 is 7((v^6)/6+v^4+2v^2)+C