What is the solution for 4y-y^{''}=10e^{-3x} ?

The solution for 4y-y^{''}=10e^{-3x} is y=c_{1}e^{2x}+c_{2}e^{-2x}-2e^{-3x}

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4y-y^{''}=10e^{-3x}

4 y - y^{^{''}} = 10 e^{- 3 x}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - 2 e^{- 3 x}

Solution steps

4 y - y^{''} (x) = 10 e^{- 3 x}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - 2 e^{- 3 x}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - 2 e^{- 3 x}

\int ln (x) + 1 d x

\int 2 sin (x) + cos (x) d x

\int_{- 1}^{2} (x^{2} + 1) d x

\int x arcsin (2 x^{2}) d x

n \to \infty lim (1^{n})

What is the solution for 4y-y^{''}=10e^{-3x} ?
The solution for 4y-y^{''}=10e^{-3x} is y=c_{1}e^{2x}+c_{2}e^{-2x}-2e^{-3x}