What is the sum from n=0 to infinity of n/n ?

The sum from n=0 to infinity of n/n is diverges

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sum from n=0 to infinity of n/n

n = 0 \sum \infty \frac{n}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{n}{n}

Simplify

= n = 1 \sum \infty 1

Every infinite sum of a non-zero constant diverges

= diverges

\frac{d}{d x} (3 x^{2} + \frac{16 x}{3} - 2)

\frac{\partial}{\partial y} (x cos (x y))

\frac{d y}{d t} = \frac{( 4 t y ^{2} )}{t ^{2} + 1}, y (0) = \frac{1}{4}

\int x^{2} - 4 x - 5 d x

y = 9 - x^{2}, - 1 \leq x \leq 1

What is the sum from n=0 to infinity of n/n ?
The sum from n=0 to infinity of n/n is diverges