What is the integral from 1 to 5 of pi(x-1) ?

The integral from 1 to 5 of pi(x-1) is 8pi

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integral from 1 to 5 of pi(x-1)

\int_{1}^{5} π (x - 1) d x

8 π

Decimal

25.13274 \dots

Solution steps

\int_{1}^{5} π (x - 1) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{1}^{5} x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{1}^{5} x d x - \int_{1}^{5} 1 d x)

\int_{1}^{5} x d x = 12

\int_{1}^{5} 1 d x = 4

= π (12 - 4)

Simplify

= 8 π

n = 1 \sum \infty n 7

\int \frac{( y + 1 ) ^{2}}{y} d y

2 - x^{2}

\frac{d}{d y} (\frac{x ^{3} - y ^{3}}{x ^{2} + y ^{2}})

\frac{d}{d x} (x^{2} + x - 4)

What is the integral from 1 to 5 of pi(x-1) ?
The integral from 1 to 5 of pi(x-1) is 8pi