What is the integral from-3 to 3 of (2x^4-3x^3) ?

The integral from-3 to 3 of (2x^4-3x^3) is 972/5

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integral from-3 to 3 of (2x^4-3x^3)

\int_{- 3}^{3} (2 x^{4} - 3 x^{3}) d x

\frac{972}{5}

Decimal

194.4

Solution steps

\int_{- 3}^{3} 2 x^{4} - 3 x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{3} 2 x^{4} d x - \int_{- 3}^{3} 3 x^{3} d x

\int_{- 3}^{3} 2 x^{4} d x = \frac{972}{5}

\int_{- 3}^{3} 3 x^{3} d x = 0

= \frac{972}{5} - 0

Simplify

= \frac{972}{5}

\int x e x d x

sin (sin (sin (x)))

x \to - 5 + lim (- \frac{9 x}{x + 5})

\frac{d}{d x} (\frac{3 e ^{x}}{2 e ^{x} + 1})

\frac{\partial}{\partial x} (x e^{2 y} sin (6 z))

What is the integral from-3 to 3 of (2x^4-3x^3) ?
The integral from-3 to 3 of (2x^4-3x^3) is 972/5