What is (\partial)/(\partial x)(2(y-1)(x+1)) ?

The answer to (\partial)/(\partial x)(2(y-1)(x+1)) is 2(y-1)

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(\partial)/(\partial x)(2(y-1)(x+1))

\frac{\partial}{\partial x} (2 (y - 1) (x + 1))

2 (y - 1)

Solution steps

\frac{\partial}{\partial x} (2 (y - 1) (x + 1))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 (y - 1) \frac{\partial}{\partial x} (x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 2 (y - 1) (\frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (1))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (1) = 0

= 2 (y - 1) (1 + 0)

Simplify

= 2 (y - 1)

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What is (\partial)/(\partial x)(2(y-1)(x+1)) ?
The answer to (\partial)/(\partial x)(2(y-1)(x+1)) is 2(y-1)