What is the slope ofintercept (5,-3),(0,-9) ?

The slope ofintercept (5,-3),(0,-9) is y= 6/5 x-9

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slope ofintercept (5,-3),(0,-9)

slope intercept

(5, - 3), (0, - 9)

y = \frac{6}{5} x - 9

Solution steps

Compute the slope

(5, - 3), (0, - 9) : m = \frac{6}{5}

Compute the

y

intercept:

b = - 9

Construct the line equation

y = mx + b

where

m = \frac{6}{5}

and

b = - 9

y = \frac{6}{5} x - 9

\frac{\partial}{\partial y} (e^{3 x} \cdot tan (y))

\frac{d}{d x} ((x^{2} + 4)^{2} (2 x^{3} - 1)^{3})

f (x) = \frac{2}{1 + e ^{- x}}

\int 7 sin^{5} (x) cos^{- \frac{3}{2}} (x) d x

\int_{0}^{2} \int_{0}^{3} (\frac{x ^{2} y ^{2}}{4}) d x d y

What is the slope ofintercept (5,-3),(0,-9) ?
The slope ofintercept (5,-3),(0,-9) is y= 6/5 x-9