What is the integral of 12x^2-10x+4 ?

The integral of 12x^2-10x+4 is 4x^3-5x^2+4x+C

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integral of 12x^2-10x+4

\int 12 x^{2} - 10 x + 4 d x

4 x^{3} - 5 x^{2} + 4 x + C

Solution steps

\int 12 x^{2} - 10 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 12 x^{2} d x - \int 10 x d x + \int 4 d x

\int 12 x^{2} d x = 4 x^{3}

\int 10 x d x = 5 x^{2}

\int 4 d x = 4 x

= 4 x^{3} - 5 x^{2} + 4 x

Add a constant to the solution

= 4 x^{3} - 5 x^{2} + 4 x + C

\frac{d}{d x} (\frac{π}{2 x ^{5}})

\int 3 x^{2} + 4 d x

x \to 3 lim (x^{2} + 7 + 5)

y = 4 x^{3} 1 - x^{2}

\int \frac{x + 4}{x - 4} d x

What is the integral of 12x^2-10x+4 ?
The integral of 12x^2-10x+4 is 4x^3-5x^2+4x+C