What is the integral from 1 to 2 of (3x^2+2x+1) ?

The integral from 1 to 2 of (3x^2+2x+1) is 11

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integral from 1 to 2 of (3x^2+2x+1)

\int_{1}^{2} (3 x^{2} + 2 x + 1) d x

11

Solution steps

\int_{1}^{2} 3 x^{2} + 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 3 x^{2} d x + \int_{1}^{2} 2 x d x + \int_{1}^{2} 1 d x

\int_{1}^{2} 3 x^{2} d x = 7

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} 1 d x = 1

= 7 + 3 + 1

Simplify

= 11

\frac{\partial}{\partial y} ((x y)^{\frac{1}{3}})

\int x 5 - 2 x d x

\int_{0}^{7} x e^{- 4 x} d x

\frac{d}{d x} (a x^{3})

f (x) = (2 x + 1)^{\frac{1}{2}}, at x = 2

What is the integral from 1 to 2 of (3x^2+2x+1) ?
The integral from 1 to 2 of (3x^2+2x+1) is 11