integral from 1 to 2 of (3x^2+2x+1)

Lösung

\int_{1}^{2} (3 x^{2} + 2 x + 1) d x

11

Schritte zur Lösung

\int_{1}^{2} 3 x^{2} + 2 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 3 x^{2} d x + \int_{1}^{2} 2 x d x + \int_{1}^{2} 1 d x

\int_{1}^{2} 3 x^{2} d x = 7

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} 1 d x = 1

= 7 + 3 + 1

Vereinfache

= 11

\int x 5 - 2 x d x

\int_{0}^{7} x e^{- 4 x} d x

t an g e n t f (x) = (2 x + 1)^{\frac{1}{2}}, at x = 2

\frac{d}{d x} (\frac{4 x}{1 + x ^{3}})

\frac{d}{d x} (2^{x} (π x^{2} + cos (x)))