What is the limit as x approaches 0 of (sin^2(6x))/7 ?

The limit as x approaches 0 of (sin^2(6x))/7 is 0

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limit as x approaches 0 of (sin^2(6x))/7

x \to 0 lim (\frac{sin ^{2} ( 6 x )}{7})

0

Solution steps

x \to 0 lim (\frac{sin ^{2} ( 6 x )}{7})

Plug in the value

x = 0

= \frac{sin ^{2} ( 6 \cdot 0 )}{7}

Simplify

\frac{sin ^{2} ( 6 \cdot 0 )}{7} : 0

= 0

\frac{1}{s ( s ^{2} - 1 )}

f (x) = \frac{1}{x + 2}, at x = 7

f (x) = \frac{x ^{2}}{x + 5}

\frac{d ^{4} y}{d x ^{4}} + 2 \frac{d ^{2} y}{d x ^{2}} + y = 0

\frac{d}{d x} (2 e^{x} + 4 x e^{x} + x^{2} e^{x})

What is the limit as x approaches 0 of (sin^2(6x))/7 ?
The limit as x approaches 0 of (sin^2(6x))/7 is 0