What is the integral of (2e^x+8x^3+6x) ?

The integral of (2e^x+8x^3+6x) is 2e^x+2x^4+3x^2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2e^x+8x^3+6x)

\int (2 e^{x} + 8 x^{3} + 6 x) d x

2 e^{x} + 2 x^{4} + 3 x^{2} + C

Solution steps

\int 2 e^{x} + 8 x^{3} + 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 e^{x} d x + \int 8 x^{3} d x + \int 6 x d x

\int 2 e^{x} d x = 2 e^{x}

\int 8 x^{3} d x = 2 x^{4}

\int 6 x d x = 3 x^{2}

= 2 e^{x} + 2 x^{4} + 3 x^{2}

Add a constant to the solution

= 2 e^{x} + 2 x^{4} + 3 x^{2} + C

\int \frac{4}{15 sin ( x ) - 8 cos ( x )} d x

y = 4 - x^{2}

\frac{d y}{d x} = \frac{x ^{2} - 1}{y ^{2} + 1}, y (- 1) = 1

n \to \infty lim (\frac{n}{- n})

x \to 3 lim (\frac{3 x - 5}{3 - x})

What is the integral of (2e^x+8x^3+6x) ?
The integral of (2e^x+8x^3+6x) is 2e^x+2x^4+3x^2+C