What is the derivative of x+ln(x) ?

The derivative of x+ln(x) is 1+1/x

What is the first derivative of x+ln(x) ?

The first derivative of x+ln(x) is 1+1/x

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derivative of

x + ln (x)

1 + \frac{1}{x}

Solution steps

\frac{d}{d x} (x + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (ln (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 1 + \frac{1}{x}

\frac{x ^{5}}{2 - x ^{4}}

y = (x^{4} + 1)^{5}

\frac{d x}{d t} = 6 (x^{2} + 1), x (\frac{π}{4}) = 1

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} - 4})

\frac{d}{d x} (4 ln ((\frac{x}{4})^{2} - 1))

What is the derivative of x+ln(x) ?
The derivative of x+ln(x) is 1+1/x
What is the first derivative of x+ln(x) ?
The first derivative of x+ln(x) is 1+1/x