What is the tangent of f(x)=x^2+x,(7,56) ?

The tangent of f(x)=x^2+x,(7,56) is y=15x-49

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tangent of f(x)=x^2+x,(7,56)

tangent of

f (x) = x^{2} + x, (7, 56)

y = 15 x - 49

Solution steps

Find the slope of

f (x) = x^{2} + x : \frac{df ( x )}{d x} = 2 x + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 15

Find the line with slope m=

15

and passing through

(7, 56) : y = 15 x - 49

y = 15 x - 49

\frac{\partial}{\partial x} (\frac{7 x - 4 y}{7 x + 4 y})

\int t \cdot e^{- s t} d t

\frac{3}{4 ( s + 1 ) ^{2} - 16}

\int_{0}^{8} 400 - 20 t d t

\int x^{3} ln (4 x) d x

What is the tangent of f(x)=x^2+x,(7,56) ?
The tangent of f(x)=x^2+x,(7,56) is y=15x-49