What is the solution for 5(dy)/(dx)+25x^4y=5x^4,y(0)=-7 ?

The solution for 5(dy)/(dx)+25x^4y=5x^4,y(0)=-7 is y= 1/5-(36)/(5e^{x^5)}

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5(dy)/(dx)+25x^4y=5x^4,y(0)=-7

5 \frac{d y}{d x} + 25 x^{4} y = 5 x^{4}, y (0) = - 7

y = \frac{1}{5} - \frac{36}{5 e ^{x^{5}}}

Solution steps

5 \frac{d y}{d x} + 25 x^{4} y = 5 x^{4}

Solve linear ODE:

y = \frac{1}{5} - \frac{36}{5 e ^{x^{5}}}

y = \frac{1}{5} - \frac{36}{5 e ^{x^{5}}}

y = x^{2} - 4, y = x + 2

c \to 1 lim (δ (x - c))

\int y^{2} + x^{2} d y

\frac{d}{d t} (ln 1 + t - t^{3})

x \to 6 - lim (∣ x - 6 ∣)

What is the solution for 5(dy)/(dx)+25x^4y=5x^4,y(0)=-7 ?
The solution for 5(dy)/(dx)+25x^4y=5x^4,y(0)=-7 is y= 1/5-(36)/(5e^{x^5)}