What is (\partial)/(\partial y)(-xsin(xy)) ?

The answer to (\partial)/(\partial y)(-xsin(xy)) is -x^2cos(xy)

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(\partial)/(\partial y)(-xsin(xy))

\frac{\partial}{\partial y} (- x sin (x y))

- x^{2} cos (x y)

Solution steps

\frac{\partial}{\partial y} (- x sin (x y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - x \frac{\partial}{\partial y} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial y} (x y)

= cos (x y) \frac{\partial}{\partial y} (x y)

\frac{\partial}{\partial y} (x y) = x

= - x cos (x y) x

Simplify

- x cos (x y) x : - x^{2} cos (x y)

= - x^{2} cos (x y)

\frac{d}{d x} (\frac{( 2 x ^{2} + 1 ) ^{4}}{2})

\frac{\partial}{\partial x} (cos (\frac{x}{y}))

\int x^{r} ln (x) d x

\frac{\partial}{\partial x} (arcsin (\frac{y}{x}))

f (x) = \frac{4 x}{x ^{2} + 1}, at x = 0

What is (\partial)/(\partial y)(-xsin(xy)) ?
The answer to (\partial)/(\partial y)(-xsin(xy)) is -x^2cos(xy)