What is the integral of-1/pi cos(pix) ?

The integral of-1/pi cos(pix) is -1/(pi^2)sin(pix)+C

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integral of-1/pi cos(pix)

\int - \frac{1}{π} cos (π x) d x

- \frac{1}{π ^{2}} sin (π x) + C

Solution steps

\int - \frac{1}{π} cos (π x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{π} \cdot \int cos (π x) d x

Apply u-substitution

: \int cos (u) \frac{1}{π} d u

= - \frac{1}{π} \cdot \int cos (u) \frac{1}{π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{π} \cdot \frac{1}{π} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= - \frac{1}{π} \cdot \frac{1}{π} sin (u)

Substitute back

u = π x

= - \frac{1}{π} \cdot \frac{1}{π} sin (π x)

Simplify

- \frac{1}{π} \cdot \frac{1}{π} sin (π x) : - \frac{1}{π ^{2}} sin (π x)

= - \frac{1}{π ^{2}} sin (π x)

Add a constant to the solution

= - \frac{1}{π ^{2}} sin (π x) + C

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What is the integral of-1/pi cos(pix) ?
The integral of-1/pi cos(pix) is -1/(pi^2)sin(pix)+C