What is the derivative of 3+2x^{1/3} ?

The derivative of 3+2x^{1/3} is 2/(3x^{2/3)}

What is the first derivative of 3+2x^{1/3} ?

The first derivative of 3+2x^{1/3} is 2/(3x^{2/3)}

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\frac{d}{d x} (3 + 2 x^{\frac{1}{3}})

\frac{2}{3 x ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (3 + 2 x^{\frac{1}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) + \frac{d}{d x} (2 x^{\frac{1}{3}})

\frac{d}{d x} (3) = 0

\frac{d}{d x} (2 x^{\frac{1}{3}}) = \frac{2}{3 x ^{\frac{2}{3}}}

= 0 + \frac{2}{3 x ^{\frac{2}{3}}}

Simplify

= \frac{2}{3 x ^{\frac{2}{3}}}

\int \frac{1 - x}{1 + x} \frac{1}{x ^{2}} d x

\frac{d}{d x} (\frac{c x}{1 + c x})

φ^{3} cos (φ^{4})

\int_{0}^{5} (6 x - x^{2})^{2} - x^{2} d x

n = 1 \sum \infty \frac{5}{2 + 3 ^{n}}

What is the derivative of 3+2x^{1/3} ?
The derivative of 3+2x^{1/3} is 2/(3x^{2/3)}
What is the first derivative of 3+2x^{1/3} ?
The first derivative of 3+2x^{1/3} is 2/(3x^{2/3)}