What is the integral of 2arcsin(x) ?

The integral of 2arcsin(x) is 2(xarcsin(x)+sqrt(1-x^2))+C

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integral of 2arcsin(x)

\int 2 arcsin (x) d x

2 (x arcsin (x) + 1 - x^{2}) + C

Solution steps

\int 2 arcsin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int arcsin (x) d x

Apply Integration By Parts

: x arcsin (x) - \int \frac{x}{1 - x ^{2}} d x

= 2 (x arcsin (x) - \int \frac{x}{1 - x ^{2}} d x)

\int \frac{x}{1 - x ^{2}} d x = - 1 - x^{2}

= 2 (x arcsin (x) - (- 1 - x^{2}))

Simplify

= 2 (x arcsin (x) + 1 - x^{2})

Add a constant to the solution

= 2 (x arcsin (x) + 1 - x^{2}) + C

\frac{d}{d x} (25 x^{2})

\frac{\partial}{\partial x} (\frac{8 x y}{x - y})

\frac{d}{d x} (sin (1.5 x))

\frac{\partial}{\partial x} (3 x^{2} - y^{2})

\frac{d y}{d x} = \frac{1}{x ^{2} - 1}

What is the integral of 2arcsin(x) ?
The integral of 2arcsin(x) is 2(xarcsin(x)+sqrt(1-x^2))+C