What is the solution for y^'=5y+y^3 ?

The solution for y^'=5y+y^3 is y=sqrt(5/(e^{-10t-c_{1))-1}},y=-sqrt(5/(e^{-10t-c_{1))-1}}

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y^'=5y+y^3

y^{^{'}} = 5 y + y^{3}

y = \frac{5}{e ^{- 10 t - c_{1}} - 1}, y = - \frac{5}{e ^{- 10 t - c_{1}} - 1}

Solution steps

y^{'} (t) = 5 y + y^{3}

Solve Bernoulli ODE:

y = \frac{5}{e ^{- 10 t - c_{1}} - 1}, y = - \frac{5}{e ^{- 10 t - c_{1}} - 1}

y = \frac{5}{e ^{- 10 t - c_{1}} - 1}, y = - \frac{5}{e ^{- 10 t - c_{1}} - 1}

\int_{- π}^{π} x^{2} cos (n x) d x

\int_{0}^{4} π (x)^{2} d x

y^{^{'}} + 3 y = 15 - e^{t}

x \to 5 - lim (e^{\frac{3}{( 5 - x )}})

\frac{d}{d x} (csc^{7} (x))

What is the solution for y^'=5y+y^3 ?
The solution for y^'=5y+y^3 is y=sqrt(5/(e^{-10t-c_{1))-1}},y=-sqrt(5/(e^{-10t-c_{1))-1}}