What is the limit as x approaches 0 of 1/2+e^{1/x} ?

The limit as x approaches 0 of 1/2+e^{1/x} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 1/2+e^{1/x}

x \to 0 lim (\frac{1}{2} + e^{\frac{1}{x}})

diverges

Solution steps

x \to 0 lim (\frac{1}{2} + e^{\frac{1}{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{2} + e^{\frac{1}{x}}) = \infty

x \to 0 - lim (\frac{1}{2} + e^{\frac{1}{x}}) = \frac{1}{2}

= diverges

\frac{d}{d x} (x (x - 2)^{\frac{2}{3}})

\frac{d}{d x} (\frac{2 x}{2 x - 1})

\int x^{5} e x^{6} + 1 d x

f (x) = - 5 x^{4}

\int (cos (2 x) e^{2 x}) d x

What is the limit as x approaches 0 of 1/2+e^{1/x} ?
The limit as x approaches 0 of 1/2+e^{1/x} is diverges